Sylvie bought 13 bagels and a container of cream cheese.Each bagel cost the same price.The cream cheese cost $2.95.Sylvie spent a total of $7.50.What was the cost of each bagel?Explain your thinking.



Answer :

Ok, first set this up as an equation with your given variables. You know that Sylvie bought 1 container of cream cheese, which is $2.95, and you know that Sylvie spent $7.50 (my best assumption is this is the subtotal) on the cream cheese and 13 bagels. As an equation, it would come out as:

[tex]7.50=2.95+13(b)[/tex]

To start solving the algebraic equation, wou can subtract 2.95 on both sides, resulting as 

[tex]4.55=13 (b)[/tex]

Now, to get "b" by itself, you must divide 13 on both sides, resulting as

[tex].35=b[/tex]

This will answer your question as the cost of 1 bagel would be $0.35 per bagel.
The total cost minus the cost of the cream cheese will give us the cost of 13 bagels, if we divide by 13 we'll get the cost of one bagel

$7.50- $2.95=$4.55 for 13 bagels

$4.55/ 13=  $.35 cent per bagel

WOW that's a great price for a bagel

Hope this helps