Answer :
you need to find the area of the blue piece so you need to multiply 12 by 9
12·9=108
108>90 so the blue piece is larger
12·9=108
108>90 so the blue piece is larger
The area of a red and a blue piece is 90 and 108 square inches. Then the blue piece is larger than the red piece.
What is a rectangle?
It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a rectangle, opposite sides are parallel and equal and each angle is 90 degrees. And its diagonals are also equal and intersect at the mid-point.
There are two large pieces of construction paper. The red piece has an area of 90 square inches while the blue piece is 12 inches long by 9 inches wide.
The area of the red piece will be
[tex]\rm A_{red} = 90[/tex]
The area of the blue piece will be
[tex]\rm A_{blue } = 12 \times 9\\\\A_{blue } = 108[/tex]
The area of a red and a blue piece is 90 and 108 square inches. Then the blue piece is larger than the red piece.
More about the rectangle link is given below.
https://brainly.com/question/10046743
