Answer :
f = 1/t
or, 440 = 1/t
thus, 440t = 1
thus, t = 1/440
thus, time period is 0.002273 seconds
or, 440 = 1/t
thus, 440t = 1
thus, t = 1/440
thus, time period is 0.002273 seconds
By using the relation between period and frequency, we conclude that the period of the fork is 0.0023 seconds.
What is the period of the vibrating fork?
We know that the relation between period and frequency is:
T = 1/f
where T is the period and f is the frequency.
In this case, we know that the frequency of the fork is 440 Hz, where:
1 Hz = 1/s
Then the period of the fork will be:
T = 1/(440 Hz) = (1/440) s = 0.0023 s
Meaning that each complete vibration of the fork takes 0.0023 seconds.
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