Answer :

[tex]d-diameter\ of\ the\ wheel\\\\d\pi=82\ in\\\\\pi\approx3.14\ then:\\\\3.14d\approx82\ in\ \ \ /:3.14\\\\d\approx\frac{82}{3.14}\ in\\\\d\approx26.11\ in\\\\d\approx26\ in\leftarrow answer[/tex]

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