Answered

a[tex] a\neq b \neq c[/tex]
a,b,c ∈ [tex] Z^{+} [/tex]
2a + b + [tex] \frac{c}{3} [/tex] =12 ⇒ max (c) = ?



Answer :

AyaZ
[tex]a=0 \\ b=1 \\ 2(0) + (1) + \frac{c}{3} =12 \\ \frac{c}{3} =12-1 \\ c=11*3 \\ max (c) = 33[/tex]

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