tayy15
tayy15
17-05-2015
Mathematics
Answered
Y^2-y=2 how do you solve?
Answer :
Panoyin
Panoyin
17-05-2015
y² - y = 2
y² - y - 2 = 2 - 2
y² - y - 2 = 0
y =
-(-1) +/- √((-1)² - 4(1)(-2))
2(1)
y =
1 +/- √(1 + 8)
2
y =
1 +/- √(9)
2
y =
1 +/- 3
2
y =
1 + 3
or y =
1 - 3
2 2
y =
4
y =
-2
2 2
y = 2 y = -1
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