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Betsey is 11 years older than Waldo. Betsey's age is 15 years less than three times Waldo's age. The system below models the relationship between Betsey's age (b) and Waldo's age (w):

b = w + 11
b = 3w − 15


Which of the following methods is correct to find Betsey's and Waldo's age?
Solve w + 11 = 3w − 15 to find the value of w.
Solve b + 11 = 3b − 15 to find the value of b.
Write the points where the graphs of the equations intersect the x-axis.
Write the points where the graphs of the equations intersect the y-axis.



Answer :

AyaZ
[tex]w + 11 = 3w - 15 \\ 2w=26 \\ w=13 \\ b = w + 11 \\ b = (13) + 11=24[/tex]

Answer:

Option 1st is correct

Solve w + 11 = 3w − 15 to find the value of w.

Step-by-step explanation:

Here b represents the Betsey's age and w represents the Waldo's age

As per the statement:

Betsey is 11 years older than Waldo. Betsey's age is 15 years less than three times Waldo's age.

The system below models the relationship between b and w:

[tex]b = w+11[/tex]  

[tex]b = 3w-15[/tex]

Equate these equations to solve for w, we have;

[tex]w+11 = 3w-15[/tex]

Add 15 to both sides we have;

[tex]w+26= 3w[/tex]

Subtract w from both sides we have;

[tex]26= 2w[/tex]

Divide both sides by 2 we have;

13 = w

or

w = 13 years

Substitute in b = w+11 we have;

b = 13 +11 = 24 years.

b = 24 years

Therefore. following methods is correct to find Betsey's and Waldo's age is:

[tex]w+11 = 3w-15[/tex]

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