Answer:
15 J
Explanation:
According to Hooke's law, the force to stretch a spring is equal to the spring constant times the displacement. The work done to stretch a spring is equal to the change in elastic energy, which is half the spring constant times the square of the displacement.
From Hooke's law:
F = kx
120 N = k (0.35 m − 0.10 m)
k = 480 N/m
The work done is:
W = EE
W = ½ kx²
W = ½ (480 N/m) (0.35 m − 0.10 m)²
W = 15 J
