Answer :
Answer:
[tex][/tex] This isn't a fair way to decide who goes first.
The probability of drawing two cards of the same color (both red or both black) in a row is not equal to the probability of drawing one red card and one black card. Since the players are drawing cards with replacement, the probabilities are independent for each draw.
When drawing one card, the probability of drawing a red card is [tex]\frac{26}{52}[/tex] (since half the deck is red) and the probability of drawing a black card is [tex]\frac{26}{52}[/tex].
For the second draw, the probability of drawing another red card is [tex]\frac{26}{52}[/tex], and the probability of drawing another black card is [tex]\frac{26}{52}[/tex].
So, the probability of drawing two cards of the same color (both red or both black) in a row is ([tex]\frac{26}{52}[/tex]) [tex] \times[/tex] ([tex]\frac{26}{52}[/tex]) + ([tex]\frac{26}{52}[/tex]) [tex] \times[/tex] ([tex]\frac{26}{52}[/tex]) = 0.5 [tex] \times[/tex] 0.5 + 0.5 [tex] \times[/tex] 0.5 = 0.5.
Therefore, the chances of Kenny going first using this method is 0.5, making it an unfair way to decide.