To find out how many moles of Al2(SO4)3 are present in 648g of the salt sample, you can follow these steps:
1. Determine the molar mass of Al2(SO4)3:
- Al: 2 atoms x 26.98 g/mol = 53.96 g/mol
- S: 3 atoms x 32.07 g/mol = 96.21 g/mol
- O: 12 atoms x 16.00 g/mol = 192.00 g/mol
Total molar mass of Al2(SO4)3 = 53.96 + 96.21 + 192.00 = 342.17 g/mol
2. Calculate the number of moles in 648g of Al2(SO4)3 using the formula:
Moles = Mass (g) / Molar mass (g/mol)
Moles = 648g / 342.17 g/mol ≈ 1.892 moles
Therefore, there are approximately 1.892 moles of Al2(SO4)3 in 648g of the salt sample.
