Write the equation of the hyperbola with co-vertices at (4, 0) and (-4, 0) and foci at (0,5)
and (0, -5).
2
y
2-4-12--1--1--1
==
16
9
25 16
=
9 16
=
16
25
=



Answer :

To find the equation of a hyperbola, we need to use the general formula for a hyperbola centered at the origin: 1. Determine the center of the hyperbola: Since the co-vertices are at (4, 0) and (-4, 0), the center is at (0, 0). 2. Calculate the distance from the center to a focus to find 'c': The distance between the center (0, 0) and one of the foci (0, 5) is 5 units. Therefore, 'c' = 5. 3. Calculate 'a' using the relationship between 'a' and 'c': For a hyperbola, a^2 + b^2 = c^2. Since b^2 = 16 (from the given equation), we can find a^2 = c^2 - b^2 = 25 - 16 = 9. Hence, a = 3. 4. Determine the equation based on the values of 'a', 'b', and the center: The standard form of the equation for a hyperbola centered at the origin is: x^2/a^2 - y^2/b^2 = 1 Therefore, substituting the values of 'a' and 'b': x^2/9 - y^2/16 = 1 Thus, the equation of the hyperbola is: x^2/9 - y^2/16 = 1