3.
The sum of interior angles of a regular polygon is 7200. Find the number of
sides of the polygon and give its name.



Answer :

msm555

Answer:

sides: 42

name: tetracontadigon

Step-by-step explanation:

The sum of the interior angles of a polygon can be found using the formula:

[tex] \boxed{\boxed{\sf \textsf{Sum of interior angles} = (n - 2) \times 180^\circ}} [/tex]

Where

  • [tex] \sf \bold{ n }[/tex] is the number of sides of the polygon.

Given that the sum of the interior angles of the polygon is [tex] \sf \bold{ 7200^\circ }[/tex], we can set up the equation:

[tex] \sf (n - 2) \times 180^\circ = 7200^\circ [/tex]

Now, let's solve for [tex] \sf \bold{ n }[/tex]:

[tex] \sf (n - 2) \times 180^\circ = 7200^\circ [/tex]

Divide both sides by [tex] \sf \bold{ 180^\circ }[/tex]:

[tex] \sf n - 2 = \dfrac{7200}{180} [/tex]

[tex] \sf n - 2 = 40 [/tex]

Add 2 to both sides:

[tex] \sf n = 40 + 2 [/tex]

[tex] \sf n = 42 [/tex]

Therefore, the polygon has [tex] \sf \bold{ \boxed{42} }[/tex] sides. Since it has 42 sides, it is called a 42-gon, or more commonly known as a tetracontadigon.