Answer:
To find the number of moles of gas in the cylinder, we can use the ideal gas law equation:
\[ PV = nRT \]
Where:
- \( P \) is the pressure of the gas (in atm)
- \( V \) is the volume of the gas (in liters)
- \( n \) is the number of moles of the gas
- \( R \) is the ideal gas constant (0.0821 L.atm/mol.K)
- \( T \) is the temperature of the gas (in Kelvin)
Given:
- \( P = 1.6 \) atm
- \( V = 28.0 \) L
- \( T = 307 \) K
We can rearrange the equation to solve for \( n \):
\[ n = \frac{PV}{RT} \]
\[ n = \frac{(1.6 \text{ atm}) \times (28.0 \text{ L})}{(0.0821 \text{ L.atm/mol.K}) \times (307 \text{ K})} \]
\[ n \approx \frac{(44.8)}{(25.237)} \]
\[ n \approx 1.78 \text{ moles} \]
So, there are approximately 1.78 moles of gas in the cylinder.
