Answer:
The pH of Ba(OH)2 will be 12.
Explanation:
Ba(OH)₂ is a strong base and will dissociate completely. Since we aren't given the acid for this equation, we'll have to work to get [OH⁻] and get to this equation:
pH + pOH = 14
Let's set up an equation of the strong base dissociating first, so we can see the mole to mole ratios for our next step:
Ba(OH)₂ ⇒ Ba⁺² + 2OH⁻
Looking at the mole to mole ratios, we know that for every one mole of Ba(OH)₂, it will yield 2 moles of [OH⁻].
We can simply times the concentration of Ba(OH)₂ to get the concentration of [OH⁻].
0.005M Ba(OH)₂ * 2 = 0.01M OH⁻
Now, we can take the concentration of OH⁻ and use the -log formula to get the amount of pOH of this problem. Simply plug these values into your calculator.
pOH = -log[OH⁻]
pOH = -log(0.01)
= 2
Now that we have pOH, we can act like pH is a variable in our first equation, subtract 2 from both sides and you will get:
pH + 2 = 14
pH = 14-2
pH = 12
Therefore the pH of Ba(OH)₂ is 12, it makes sense because Ba(OH)₂ is a strong base, meaning the pH would be higher.
I hope this helps!