Two marbles are chosen at random, one at a time from a box that contains 7 marbles, 5 red and 2 green. Find the probability of drawing 2 red marbles when the first marble is replaced before the second marble is chosen.



Answer :

can130

Answer:

0.51 or 25/49

Step-by-step explanation:

To find the probability of drawing 2 red marbles when the first marble is replaced before the second marble is chosen, we can use the concept of independent events and the multiplication rule for independent events.

The probability of drawing a red marble on the first draw is 5/7 because there are 5 red marbles out of 7 total marbles.

Since the first marble is replaced before the second draw, the probability of drawing a red marble on the second draw is also 5/7.

Using the multiplication rule for independent events, we can multiply the probabilities of the two independent events to find the probability of both events occurring:

P(2 red marbles) = (5/7) * (5/7) = 25/49 ≈ 0.51

Therefore, the probability of drawing 2 red marbles when the first marble is replaced before the second marble is chosen is approximately 0.51 or 25/49.