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A 25 kg box has an initial velocity of 2 m/s. It is pushed along a board for 6 seconds with a force of 150N with friction present between the board and the box. The coefficient of friction is 0.25 for the box and board materials. How much is the normal force on the block?



Answer :

MathPhys

Answer:

245 N

Explanation:

According to Newton's second law of motion, the net force (∑F) on an object is equal to its mass (m) times its acceleration (a). Drawing a free body diagram, there are four forces on the box. Assuming the board is horizontal, the direction of the forces are:

  • Weight force mg pulling down
  • Normal force N pushing up
  • Friction force Nμ pushing left, where μ is the coefficient of friction
  • Applied force P pushing right

Summing the forces in the vertical direction:

∑F = ma

N − mg = 0

N = mg

N = (25 kg) (9.8 m/s²)

N = 245 N

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