[tex]\huge{\bf{{\underline{\colorbox{red} {\color{black} {Answer}}}}}}[/tex]
$4a^2 + 2b - 3c$
When a = -1/2, b = 3, and c = -2, the value of the expression is:
$4\left(-\frac{1}{2}\right)^2 + 2(3) - 3(-2) = 1 + 6 - (-6) = 1$
Therefore, the value of the expression $4a^2 + 2b - 3c$ when a = -1/2, b = 3, and c = -2 is 1.
