Sure, let's analyze this step by step.
When we toss a single coin, there are two possible outcomes: heads (H) or tails (T). Therefore:
- Tossing 1 coin results in [tex]\(2\)[/tex] possible outcomes.
When we toss more coins, we need to consider the combinations of outcomes for all coins. Specifically:
- Tossing 2 coins results in [tex]\(2 \times 2 = 4\)[/tex] possible outcomes (HH, HT, TH, TT).
The number of possible outcomes is given by [tex]\(2^n\)[/tex], where [tex]\(n\)[/tex] is the number of coins. So, for 6 coins, the total number of possible outcomes is:
[tex]\[
2^6
\][/tex]
Calculating this, we get:
[tex]\[
2^6 = 64
\][/tex]
So, if six coins are tossed simultaneously, the number of possible events (outcomes) is [tex]\(64\)[/tex].
Therefore, the correct answer is:
A. 64
