Answered

The current in a coil of 500 turns is changed from zero to 5.43 Amp. There by producing a flux of 8.52 x 10-4 webers. What is the self-inductance of the coil?



Answer :

Answer:

The magnetic flux through an inductor is the self inductance of coil times the current through it.

Thus

ϕ

=

L

I

=

50

×

10

−

3

H

×

8

×

10

−

3

A

=

4

×

10

−

4

W

b

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