To determine the number of moles of sodium hydroxide (NaOH) needed to neutralize 25 mL of 0.1 M hydrochloric acid (HCl), follow these steps:
1. Calculate the moles of HCl.
- Molarity of HCl = 0.1 M
- Volume of HCl = 25 mL = 0.025 L
Moles of HCl = Molarity * Volume
Moles of HCl = 0.1 * 0.025
Moles of HCl = 0.0025 moles
2. Since the reaction between NaOH and HCl is 1:1, the moles of NaOH needed will be equal to the moles of HCl.
Moles of NaOH needed = 0.0025 moles