Answer :
To determine the molar concentration of a solution with a given volume and mass of solute, we can follow these steps:
### Step 1: Determine the number of moles of the solute (Ca₃(PO₄)₂)
First, we need to convert the mass of the solute from grams to moles. This conversion uses the molar mass of the solute.
Given:
- Mass of solute (Ca₃(PO₄)₂) = 660 g
- Molar mass of Ca₃(PO₄)₂ = 310.18 g/mol
To find the number of moles ([tex]\(n\)[/tex]):
[tex]\[ n = \frac{\text{mass of solute}}{\text{molar mass}} \][/tex]
[tex]\[ n = \frac{660 \, \text{g}}{310.18 \, \text{g/mol}} \][/tex]
[tex]\[ n \approx 2.1278 \, \text{moles} \][/tex]
### Step 2: Calculate the molar concentration
Next, we use the volume of the solution to find the molar concentration. Molar concentration (M) is defined as the number of moles of solute per liter of solution.
Given:
- Volume of the solution = 1.5 L
To find the molar concentration ([tex]\(C\)[/tex]):
[tex]\[ C = \frac{\text{number of moles of solute}}{\text{volume of solution}} \][/tex]
[tex]\[ C = \frac{2.1278 \, \text{moles}}{1.5 \, \text{L}} \][/tex]
[tex]\[ C \approx 1.4185 \, \text{mol/L} \][/tex]
### Conclusion
The molar concentration of the solution is approximately [tex]\( 1.4185 \, \text{mol/L} \)[/tex].
### Step 1: Determine the number of moles of the solute (Ca₃(PO₄)₂)
First, we need to convert the mass of the solute from grams to moles. This conversion uses the molar mass of the solute.
Given:
- Mass of solute (Ca₃(PO₄)₂) = 660 g
- Molar mass of Ca₃(PO₄)₂ = 310.18 g/mol
To find the number of moles ([tex]\(n\)[/tex]):
[tex]\[ n = \frac{\text{mass of solute}}{\text{molar mass}} \][/tex]
[tex]\[ n = \frac{660 \, \text{g}}{310.18 \, \text{g/mol}} \][/tex]
[tex]\[ n \approx 2.1278 \, \text{moles} \][/tex]
### Step 2: Calculate the molar concentration
Next, we use the volume of the solution to find the molar concentration. Molar concentration (M) is defined as the number of moles of solute per liter of solution.
Given:
- Volume of the solution = 1.5 L
To find the molar concentration ([tex]\(C\)[/tex]):
[tex]\[ C = \frac{\text{number of moles of solute}}{\text{volume of solution}} \][/tex]
[tex]\[ C = \frac{2.1278 \, \text{moles}}{1.5 \, \text{L}} \][/tex]
[tex]\[ C \approx 1.4185 \, \text{mol/L} \][/tex]
### Conclusion
The molar concentration of the solution is approximately [tex]\( 1.4185 \, \text{mol/L} \)[/tex].
