Answer :
To find the [tex]\( y \)[/tex]-intercept of the line given by the equation [tex]\( y = 5x - 21 \)[/tex], you need to determine the value of [tex]\( y \)[/tex] when [tex]\( x \)[/tex] is 0.
The general form of a linear equation is [tex]\( y = mx + b \)[/tex], where:
- [tex]\( m \)[/tex] is the slope of the line.
- [tex]\( b \)[/tex] is the [tex]\( y \)[/tex]-intercept, which is the value of [tex]\( y \)[/tex] when [tex]\( x \)[/tex] is 0.
Given the equation [tex]\( y = 5x - 21 \)[/tex]:
- [tex]\( m \)[/tex] (the slope) is 5.
- [tex]\( b \)[/tex] (the [tex]\( y \)[/tex]-intercept) is -21.
To find the [tex]\( y \)[/tex]-intercept, substitute [tex]\( x = 0 \)[/tex] into the equation:
[tex]\[ y = 5(0) - 21 \][/tex]
[tex]\[ y = 0 - 21 \][/tex]
[tex]\[ y = -21 \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept is [tex]\((0, -21)\)[/tex].
The correct answer is:
A. [tex]\((0, -21)\)[/tex]
The general form of a linear equation is [tex]\( y = mx + b \)[/tex], where:
- [tex]\( m \)[/tex] is the slope of the line.
- [tex]\( b \)[/tex] is the [tex]\( y \)[/tex]-intercept, which is the value of [tex]\( y \)[/tex] when [tex]\( x \)[/tex] is 0.
Given the equation [tex]\( y = 5x - 21 \)[/tex]:
- [tex]\( m \)[/tex] (the slope) is 5.
- [tex]\( b \)[/tex] (the [tex]\( y \)[/tex]-intercept) is -21.
To find the [tex]\( y \)[/tex]-intercept, substitute [tex]\( x = 0 \)[/tex] into the equation:
[tex]\[ y = 5(0) - 21 \][/tex]
[tex]\[ y = 0 - 21 \][/tex]
[tex]\[ y = -21 \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept is [tex]\((0, -21)\)[/tex].
The correct answer is:
A. [tex]\((0, -21)\)[/tex]
A because according to the information Gaven on the problem you are trying to solve on.
