Answer :
To determine which options could be an isotope of bromine ([tex]$Br$[/tex]), we will use the properties of isotopes and the periodic table.
Bromine ([tex]$Br$[/tex]) has an atomic number [tex]\( Z = 35 \)[/tex]. This atomic number is crucial because it identifies the element as bromine. Isotopes of an element have the same atomic number but different mass numbers ([tex]\( A \)[/tex]).
Now let's examine each option:
1. Option 1: [tex]\( Z = 79, A = 196 \)[/tex]
- The atomic number [tex]\( Z = 79 \)[/tex] does not correspond to bromine's atomic number, which is 35. This could not be an isotope of bromine since the atomic number specifies a different element (gold in this case).
2. Option 2: [tex]\( Z = 35, A = 79 \)[/tex]
- The atomic number [tex]\( Z = 35 \)[/tex] matches that of bromine, indicating this is indeed bromine. The mass number [tex]\( A = 79 \)[/tex] could represent one isotope of bromine.
3. Option 3: [tex]\( A = 79, N = 44 \)[/tex]
- The mass number [tex]\( A = 79 \)[/tex] and the neutron number [tex]\( N = 44 \)[/tex]. To find the atomic number [tex]\( Z \)[/tex], we use:
[tex]\[ Z = A - N = 79 - 44 = 35 \][/tex]
- This atomic number [tex]\( Z = 35 \)[/tex] matches that of bromine. Therefore, this configuration could represent an isotope of bromine.
4. Option 4: [tex]\( Z = 44, N = 44 \)[/tex]
- The atomic number [tex]\( Z = 44 \)[/tex] does not correspond to bromine's atomic number, which is 35. This could not be an isotope of bromine since the atomic number specifies a different element (ruthenium in this case).
After examining all options, the ones that match the criteria for being an isotope of bromine ([tex]\( Z = 35 \)[/tex]) are:
- Option 2: [tex]\( Z = 35, A = 79 \)[/tex]
- Option 3: [tex]\( A = 79, N = 44 \)[/tex]
Thus, the correct options are 2 and 3.
Bromine ([tex]$Br$[/tex]) has an atomic number [tex]\( Z = 35 \)[/tex]. This atomic number is crucial because it identifies the element as bromine. Isotopes of an element have the same atomic number but different mass numbers ([tex]\( A \)[/tex]).
Now let's examine each option:
1. Option 1: [tex]\( Z = 79, A = 196 \)[/tex]
- The atomic number [tex]\( Z = 79 \)[/tex] does not correspond to bromine's atomic number, which is 35. This could not be an isotope of bromine since the atomic number specifies a different element (gold in this case).
2. Option 2: [tex]\( Z = 35, A = 79 \)[/tex]
- The atomic number [tex]\( Z = 35 \)[/tex] matches that of bromine, indicating this is indeed bromine. The mass number [tex]\( A = 79 \)[/tex] could represent one isotope of bromine.
3. Option 3: [tex]\( A = 79, N = 44 \)[/tex]
- The mass number [tex]\( A = 79 \)[/tex] and the neutron number [tex]\( N = 44 \)[/tex]. To find the atomic number [tex]\( Z \)[/tex], we use:
[tex]\[ Z = A - N = 79 - 44 = 35 \][/tex]
- This atomic number [tex]\( Z = 35 \)[/tex] matches that of bromine. Therefore, this configuration could represent an isotope of bromine.
4. Option 4: [tex]\( Z = 44, N = 44 \)[/tex]
- The atomic number [tex]\( Z = 44 \)[/tex] does not correspond to bromine's atomic number, which is 35. This could not be an isotope of bromine since the atomic number specifies a different element (ruthenium in this case).
After examining all options, the ones that match the criteria for being an isotope of bromine ([tex]\( Z = 35 \)[/tex]) are:
- Option 2: [tex]\( Z = 35, A = 79 \)[/tex]
- Option 3: [tex]\( A = 79, N = 44 \)[/tex]
Thus, the correct options are 2 and 3.
