Consider circle [tex]$T$[/tex] with radius [tex]$24 \text{ in.}$[/tex] and [tex]$\theta = \frac{5 \pi}{6}$[/tex] radians.

What is the length of minor arc [tex]SV[/tex]?

A. [tex][tex]$20 \pi$[/tex][/tex] in.
B. [tex]$28 \pi$[/tex] in.
C. [tex]$40 \pi$[/tex] in.
D. [tex][tex]$63 \pi$[/tex][/tex] in.



Answer :

To find the length of the minor arc [tex]\( SV \)[/tex] in circle [tex]\( T \)[/tex], you need to use the formula for the arc length of a circle, which is given by:

[tex]\[ \text{Arc Length} = \theta \times r \][/tex]

where:
- [tex]\( \theta \)[/tex] is the central angle in radians
- [tex]\( r \)[/tex] is the radius of the circle

In this problem, the radius [tex]\( r \)[/tex] of the circle is given as [tex]\( 24 \)[/tex] inches, and the central angle [tex]\( \theta \)[/tex] is given as [tex]\( \frac{5 \pi}{6} \)[/tex] radians.

Substitute these values into the formula:

[tex]\[ \text{Arc Length} = \frac{5 \pi}{6} \times 24 \][/tex]

Now, multiply these numbers:

[tex]\[ \text{Arc Length} = \frac{5 \pi}{6} \times 24 = 20 \pi \][/tex]

To ascertain the right answer choice, compare [tex]\( 20 \pi \)[/tex] with the given options:

- [tex]\( 20 \pi \)[/tex] in.
- [tex]\( 28 \pi \)[/tex] in.
- [tex]\( 40 \pi \)[/tex] in.
- [tex]\( 63 \pi \)[/tex] in.

The correct answer is:

[tex]\[ 20 \pi \text{ in.} \][/tex]

Thus, the length of the minor arc [tex]\( SV \)[/tex] is [tex]\( 20 \pi \)[/tex] inches.