Answer :
To solve the problem, we need to determine the probability that a passenger prefers to sit in the front of the plane and prefers a window seat. Here's the step-by-step solution:
1. Identify the number of passengers who prefer both the front and a window seat:
According to the given table, the number of passengers who prefer to sit in the front and prefer a window seat is 8.
2. Find the total number of surveyed passengers:
The total number of passengers surveyed is 36, as given in the table.
3. Calculate the probability:
The probability of an event is given by the ratio of the favorable outcomes to the total outcomes. In this case, the probability [tex]\( P \)[/tex] that a passenger prefers to sit in the front of the plane and prefers a window seat is:
[tex]\[ P = \frac{\text{Number of passengers preferring front and window seat}}{\text{Total number of passengers}} \][/tex]
Substituting the values, we get:
[tex]\[ P = \frac{8}{36} = \frac{2}{9} \][/tex]
Therefore, the correct answer is:
A. [tex]\(\frac{2}{9}\)[/tex]
1. Identify the number of passengers who prefer both the front and a window seat:
According to the given table, the number of passengers who prefer to sit in the front and prefer a window seat is 8.
2. Find the total number of surveyed passengers:
The total number of passengers surveyed is 36, as given in the table.
3. Calculate the probability:
The probability of an event is given by the ratio of the favorable outcomes to the total outcomes. In this case, the probability [tex]\( P \)[/tex] that a passenger prefers to sit in the front of the plane and prefers a window seat is:
[tex]\[ P = \frac{\text{Number of passengers preferring front and window seat}}{\text{Total number of passengers}} \][/tex]
Substituting the values, we get:
[tex]\[ P = \frac{8}{36} = \frac{2}{9} \][/tex]
Therefore, the correct answer is:
A. [tex]\(\frac{2}{9}\)[/tex]
