Yazmin has $50,000 to invest and is looking for an account where the initial investment will grow to $85,000 after 10 years. What interest rate does she need in order to guarantee the money she needs?



Answer :

Answer:

Yazmin needs an interest rate of 5.45%.

Step-by-step explanation:

Compound Interest Formula (Yearly)

To know how much money an account makes from its initial deposit, the interest rate and, the number years that elapsed, a formula can be used to calculate as such.

                                          [tex]A=P\left(1+r)^t[/tex],

where P is the initial amount that's placed into the account, r is the interest rate in decimal form, t is the time that passes in years and A is the value of the account at time t years.

Solving the Problem

Yazmin want's her $50,000 to grow to $85,000 in 10 years, meaning that she'll need to open a  yearly compound interest account.

The problem asks for the value of r in percentage form, to do that we must find the value of r in its original decimal form.

Plugging the appropriate values and variables into the equation we have,

                                         [tex]85000=50000(1+r)^1^0[/tex].

Now, we rearrange the equation to isolate and compute the r variable!

                                           [tex]\dfrac{85000}{50000} =(1+r)^1^0[/tex]

                                             [tex]1.7=(1+r)^1^0[/tex]

                                              [tex]\sqrt[10]{1.7} =1+r[/tex]

                                              [tex]\sqrt[10]{1.7} -1=r[/tex]

                                                [tex]0.0545=r[/tex]

To transform the interest rate into percentage form we move the decimal point two places to the right. So, the interest rate Yazmin needs is 5.45%.

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