To find the extremes of the given proportion [tex]\(\frac{3}{4} = \frac{6}{8}\)[/tex], we need to identify the first and last terms in this equation.
1. The proportion given is [tex]\(\frac{3}{4} = \frac{6}{8}\)[/tex].
2. In any proportion [tex]\(\frac{a}{b} = \frac{c}{d}\)[/tex], the first term [tex]\(a\)[/tex] and the last term [tex]\(d\)[/tex] are known as the extremes.
So, for the given proportion:
- The first term (numerator of the first fraction) is 3.
- The last term (denominator of the second fraction) is 8.
Therefore, the extremes of the proportion [tex]\(\frac{3}{4} = \frac{6}{8}\)[/tex] are 3 and 8.
Hence, the correct answer is:
C. 3 and 8
