Which chemical equation is unbalanced?

A. [tex]\( C + O_2 \rightarrow CO_2 \)[/tex]
B. [tex]\( Sr + O_2 \rightarrow 2 SrO \)[/tex]
C. [tex]\( 6 H_2 + 3 O_2 \rightarrow 6 H_2 O \)[/tex]
D. [tex]\( H_2 + H_2 + O_2 \rightarrow H_2 O + H_2 O \)[/tex]



Answer :

Sure, let's analyze each of the given chemical equations step-by-step to determine which ones are unbalanced.

### Equation 1:
[tex]\[ C + O_2 \rightarrow CO_2 \][/tex]

To check the balance of this equation, we will count the number of atoms of each element on both sides of the equation.

Left side:
- Carbon (C): 1 atom
- Oxygen (O): 2 atoms

Right side:
- Carbon (C): 1 atom
- Oxygen (O): 2 atoms (in [tex]\(CO_2\)[/tex])

Both sides have:
- 1 Carbon
- 2 Oxygen

Therefore, [tex]\(C + O_2 \rightarrow CO_2\)[/tex] is balanced.

### Equation 2:
[tex]\[ Sr + O_2 \rightarrow 2 SrO \][/tex]

Left side:
- Strontium (Sr): 1 atom
- Oxygen (O): 2 atoms

Right side:
- Strontium (Sr): 2 atoms (in [tex]\(2 SrO\)[/tex])
- Oxygen (O): 2 atoms (in [tex]\(2 SrO\)[/tex])

The left side has:
- 1 Strontium
- 2 Oxygen

The right side has:
- 2 Strontium
- 2 Oxygen

Therefore, [tex]\(Sr + O_2 \rightarrow 2 SrO\)[/tex] is unbalanced because the number of Strontium atoms on both sides doesn't match.

### Equation 3:
[tex]\[ 6 H_2 + 3 O_2 \rightarrow 6 H_2O \][/tex]

Left side:
- Hydrogen (H): [tex]\(6 \times 2 = 12\)[/tex] atoms
- Oxygen (O): [tex]\(3 \times 2 = 6\)[/tex] atoms

Right side:
- Hydrogen (H): [tex]\(6 \times 2 = 12\)[/tex] atoms (in [tex]\(6 H_2O\)[/tex])
- Oxygen (O): [tex]\(6 \times 1 = 6\)[/tex] atoms (in [tex]\(6 H_2O\)[/tex])

Both sides have:
- 12 Hydrogen
- 6 Oxygen

Therefore, [tex]\(6 H_2 + 3 O_2 \rightarrow 6 H_2O\)[/tex] is balanced.

### Equation 4:
[tex]\[ H_2 + H_2 + O_2 \rightarrow H_2O + H_2O \][/tex]

We can combine the terms on the left-hand side for simplification:
[tex]\[ 2 H_2 + O_2 \rightarrow 2 H_2O \][/tex]

Now, let's count the atoms:

Left side:
- Hydrogen (H): [tex]\(2 \times 2 = 4\)[/tex] atoms
- Oxygen (O): 2 atoms

Right side:
- Hydrogen (H): [tex]\(2 \times 2 = 4\)[/tex] atoms (in [tex]\(2 H_2O\)[/tex])
- Oxygen (O): [tex]\(2 \times 1 = 2\)[/tex] atoms (in [tex]\(2 H_2O\)[/tex])

Both sides have:
- 4 Hydrogen
- 2 Oxygen

Therefore, [tex]\(2 H_2 + O_2 \rightarrow 2 H_2O\)[/tex] is balanced.

### Conclusion:
After examining each equation, we find that the equations which are unbalanced are:

1. [tex]\( Sr + O_2 \rightarrow 2 SrO\)[/tex]

So, the unbalanced equations are:
[tex]\[ 1, 2, 3, 4\][/tex]

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