Which of the following is a vertical stretch of the parent function [tex]\( f(x) = x^2 \)[/tex]?

A. [tex]\( y = 4x^2 \)[/tex]
B. [tex]\( y = \frac{1}{4} + x^2 \)[/tex]
C. [tex]\( y = \left(\frac{1}{4} x\right)^2 \)[/tex]
D. [tex]\( y = x^2 - 4 \)[/tex]



Answer :

To determine which equation represents a vertical stretch of the parent function [tex]\( f(x)=x^2 \)[/tex], let's examine each option by evaluating them at [tex]\( x = 1 \)[/tex].

1. Option [tex]\( y = 4x^2 \)[/tex]:
[tex]\[ y = 4 \cdot (1)^2 = 4 \][/tex]
This equation multiplies the original parent function [tex]\( x^2 \)[/tex] by 4, making the graph steeper. Hence, it represents a vertical stretch.

2. Option [tex]\( y = \frac{1}{4} + x^2 \)[/tex]:
[tex]\[ y = \frac{1}{4} + (1)^2 = \frac{1}{4} + 1 = 1.25 \][/tex]
This equation adds a constant to the parent function [tex]\( x^2 \)[/tex] which translates the graph vertically but does not stretch it.

3. Option [tex]\( y = \left(\frac{1}{4}x\right)^2 \)[/tex]:
[tex]\[ y = \left(\frac{1}{4} \cdot 1\right)^2 = \left(\frac{1}{4}\right)^2 = 0.0625 \][/tex]
This equation compresses the graph horizontally by a factor of 4 (since the x-term is multiplied by [tex]\( \frac{1}{4} \)[/tex]) and then squares the result. This does not represent a vertical stretch.

4. Option [tex]\( y = x^2 - 4 \)[/tex]:
[tex]\[ y = (1)^2 - 4 = 1 - 4 = -3 \][/tex]
This equation subtracts a constant from the parent function [tex]\( x^2 \)[/tex], which translates the graph downward but does not change its shape in terms of stretching.

Therefore, the equation that represents a vertical stretch of the parent function [tex]\( f(x) = x^2 \)[/tex] is [tex]\( y = 4x^2 \)[/tex].

Hence, the correct choice is:
[tex]\( y = 4x^2 \)[/tex].