A supervisor finds the mean number of miles that the employees in a department live from work: [tex]$\bar{x} = 29$[/tex] and [tex]$\sigma = 6$[/tex]. Which mileage is within a [tex]$z$[/tex]-score of -1.5?

A. 21 miles
B. 24 miles
C. 36 miles
D. 41 miles



Answer :

Sure! Let's solve this step by step:

1. Understanding the problem:
We need to find the mileage corresponding to a given z-score. The mean distance ([tex]\(\bar{x}\)[/tex]) that employees live from work is 29 miles, and the standard deviation ([tex]\(\sigma\)[/tex]) is 6 miles. We are given a z-score of -1.5 and need to identify which of the given options (21, 24, 36, and 41 miles) is closest to the actual mileage associated with this z-score.

2. Formula for z-score:
The formula to calculate the mileage from a z-score is:
[tex]\[ X = \bar{x} + z \cdot \sigma \][/tex]
where [tex]\(X\)[/tex] is the mileage, [tex]\(\bar{x}\)[/tex] is the mean mileage, [tex]\(z\)[/tex] is the z-score, and [tex]\(\sigma\)[/tex] is the standard deviation.

3. Substitute the given values:
[tex]\[ X = 29 + (-1.5) \cdot 6 \][/tex]

4. Calculate the mileage:
[tex]\[ X = 29 - 9 = 20 \][/tex]
The mileage corresponding to a z-score of -1.5 is 20 miles.

5. Identify the closest option:
Comparing the calculated mileage (20 miles) with the given options:
- 21 miles
- 24 miles
- 36 miles
- 41 miles

The closest value to 20 miles among these options is 21 miles.

Therefore, the mileage within a z-score of -1.5 is approximately 21 miles.

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