The power [tex][tex]$g^2$[/tex][/tex] is equivalent to 81. What is the value of [tex][tex]$9^{-2}$[/tex][/tex]?

A. [tex]-81[/tex]
B. [tex]-9[/tex]
C. [tex]\frac{1}{81}[/tex]
D. [tex]\frac{1}{9}[/tex]



Answer :

To solve the given problem, we need to break it down step by step.

Firstly, we are informed that the power [tex]\( g^2 \)[/tex] is equivalent to 81. This implies:

[tex]\[ g^2 = 81 \][/tex]

To find [tex]\( g \)[/tex], we take the square root of both sides:

[tex]\[ g = \sqrt{81} \][/tex]

This implies:

[tex]\[ g = 9 \quad \text{or} \quad g = -9 \][/tex]

Both [tex]\( g = 9 \)[/tex] and [tex]\( g = -9 \)[/tex] are valid solutions. However, to find the value of [tex]\( 9^{-2} \)[/tex], we can use [tex]\( g = 9 \)[/tex] (since using [tex]\( g = -9 \)[/tex] would lead to the same result as they both correspond to 9 squared positive).

Next, we need to determine [tex]\( 9^{-2} \)[/tex].

By the definition of negative exponents:

[tex]\[ 9^{-2} = \frac{1}{9^2} \][/tex]

We then calculate [tex]\( 9^2 \)[/tex]:

[tex]\[ 9^2 = 81 \][/tex]

Therefore:

[tex]\[ 9^{-2} = \frac{1}{81} \][/tex]

Hence, the correct value is:

[tex]\[\boxed{\frac{1}{81}} \][/tex]

So, [tex]\( 9^{-2} = \frac{1}{81} \)[/tex].