Answer :
Let's analyze the given sequences to determine if they are indeed the same.
We begin with the examined sequence: [tex]\(a_1=2\)[/tex], [tex]\(a_2=4\)[/tex], [tex]\(a_3=8\)[/tex], [tex]\(a_4=16\)[/tex], [tex]\(a_5=32\)[/tex], ...
Now, let's consider the recursive definition for this sequence:
- [tex]\(a_1=2\)[/tex]
- For [tex]\(n>1\)[/tex], [tex]\(a_n = 2 \cdot a_{n-1}\)[/tex]
We'll calculate the terms of the sequence using this recursive definition step by step.
1. [tex]\(a_1 = 2\)[/tex]
2. [tex]\(a_2 = 2 \cdot a_1 = 2 \cdot 2 = 4\)[/tex]
3. [tex]\(a_3 = 2 \cdot a_2 = 2 \cdot 4 = 8\)[/tex]
4. [tex]\(a_4 = 2 \cdot a_3 = 2 \cdot 8 = 16\)[/tex]
5. [tex]\(a_5 = 2 \cdot a_4 = 2 \cdot 16 = 32\)[/tex]
Now, compare the terms from the recursive definition with the given sequence:
- Given sequence: [tex]\(2, 4, 8, 16, 32\)[/tex]
- Calculated sequence: [tex]\(2, 4, 8, 16, 32\)[/tex]
Since the terms of the sequences match exactly, we can conclude that the given sequence is, indeed, the same as the sequence defined recursively.
Hence, the answer is A. True.
We begin with the examined sequence: [tex]\(a_1=2\)[/tex], [tex]\(a_2=4\)[/tex], [tex]\(a_3=8\)[/tex], [tex]\(a_4=16\)[/tex], [tex]\(a_5=32\)[/tex], ...
Now, let's consider the recursive definition for this sequence:
- [tex]\(a_1=2\)[/tex]
- For [tex]\(n>1\)[/tex], [tex]\(a_n = 2 \cdot a_{n-1}\)[/tex]
We'll calculate the terms of the sequence using this recursive definition step by step.
1. [tex]\(a_1 = 2\)[/tex]
2. [tex]\(a_2 = 2 \cdot a_1 = 2 \cdot 2 = 4\)[/tex]
3. [tex]\(a_3 = 2 \cdot a_2 = 2 \cdot 4 = 8\)[/tex]
4. [tex]\(a_4 = 2 \cdot a_3 = 2 \cdot 8 = 16\)[/tex]
5. [tex]\(a_5 = 2 \cdot a_4 = 2 \cdot 16 = 32\)[/tex]
Now, compare the terms from the recursive definition with the given sequence:
- Given sequence: [tex]\(2, 4, 8, 16, 32\)[/tex]
- Calculated sequence: [tex]\(2, 4, 8, 16, 32\)[/tex]
Since the terms of the sequences match exactly, we can conclude that the given sequence is, indeed, the same as the sequence defined recursively.
Hence, the answer is A. True.