Using the activity series provided, which reactants will form products?

[tex]\[ \text{Na} \ \textgreater \ \text{Mg} \ \textgreater \ \text{Al} \ \textgreater \ \text{Mn} \ \textgreater \ \text{Zn} \ \textgreater \ \text{Cr} \ \textgreater \ \text{Fe} \ \textgreater \ \text{Cd} \ \textgreater \ \text{Co} \ \textgreater \ \text{Ni} \ \textgreater \ \text{Sn} \ \textgreater \ \text{Pb} \ \textgreater \ \text{H} \ \textgreater \ \text{Sb} \ \textgreater \ \text{Bi} \ \textgreater \ \text{Cu} \ \textgreater \ \text{Ag} \][/tex]

[tex]\[ \text{Ag} + \text{NaNO}_3 \rightarrow \][/tex]
[tex]\[ \text{Fe} + \text{Al}_2\text{O}_3 \rightarrow \][/tex]
[tex]\[ \text{Ni} + \text{NaCl} \rightarrow \][/tex]
[tex]\[ \text{Fe} + \text{Cu}\left(\text{NO}_3\right)_2 \rightarrow \][/tex]

Question

24-06-2024
Chemistry

Answered

Using the activity series provided, which reactants will form products?

[tex]\[ \text{Na} \ \textgreater \ \text{Mg} \ \textgreater \ \text{Al} \ \textgreater \ \text{Mn} \ \textgreater \ \text{Zn} \ \textgreater \ \text{Cr} \ \textgreater \ \text{Fe} \ \textgreater \ \text{Cd} \ \textgreater \ \text{Co} \ \textgreater \ \text{Ni} \ \textgreater \ \text{Sn} \ \textgreater \ \text{Pb} \ \textgreater \ \text{H} \ \textgreater \ \text{Sb} \ \textgreater \ \text{Bi} \ \textgreater \ \text{Cu} \ \textgreater \ \text{Ag} \][/tex]

[tex]\[ \text{Ag} + \text{NaNO}_3 \rightarrow \][/tex]
[tex]\[ \text{Fe} + \text{Al}_2\text{O}_3 \rightarrow \][/tex]
[tex]\[ \text{Ni} + \text{NaCl} \rightarrow \][/tex]
[tex]\[ \text{Fe} + \text{Cu}\left(\text{NO}_3\right)_2 \rightarrow \][/tex]

Answer :

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GinnyAnswer GinnyAnswer · Answer 1 · 2024-06-24T02:39:28-04:00

To determine which reactions will form products, we can use the activity series of metals. The activity series ranks metals according to their reactivity, with more reactive metals able to displace less reactive metals from compounds.

Using the activity series provided:
[tex]$ Na > Mg > Al > Mn > Zn > Cr > Fe > Cd > Co > Ni > Sn > Pb > H > Sb > Bi > Cu > Ag $[/tex]

### Reaction 1:
[tex]$ Ag + NaNO_3 \rightarrow $[/tex]

- Silver (Ag) and Sodium (Na) are the metals involved.
- Looking at the activity series, Sodium (Na) is higher, and thus more reactive, than Silver (Ag).

Since Na is more reactive than Ag, Silver cannot displace Sodium from NaNO3, and no reaction will occur.

### Reaction 2:
[tex]$ Fe + Al_2O_3 \rightarrow $[/tex]

- Iron (Fe) and Aluminum (Al) are the metals involved.
- According to the activity series, Aluminum (Al) is higher, and thus more reactive, than Iron (Fe).

Since Al is more reactive than Fe, Iron cannot displace Aluminum from Al2O3, and no reaction will occur.

### Reaction 3:
[tex]$ Ni + NaCl \rightarrow $[/tex]

- Nickel (Ni) and Sodium (Na) are the metals involved.
- According to the activity series, Sodium (Na) is higher, and thus more reactive, than Nickel (Ni).

Since Na is more reactive than Ni, Nickel cannot displace Sodium from NaCl, and no reaction will occur.

### Reaction 4:
[tex]$ Fe + Cu(NO_3)_2 \rightarrow $[/tex]

- Iron (Fe) and Copper (Cu) are the metals involved.
- According to the activity series, Iron (Fe) is higher, and thus more reactive, than Copper (Cu).

Since Fe is more reactive than Cu, Iron can displace Copper from Cu(NO3)2, and a reaction will occur, forming Iron(III) Nitrate (Fe(NO3)2) and Copper (Cu).

### Summary:
After examining the activity of each metal involved in the reactions:

1. [tex]$ Ag + NaNO_3 \rightarrow $[/tex] - No reaction (False)
2. [tex]$ Fe + Al_2O_3 \rightarrow $[/tex] - No reaction (False)
3. [tex]$ Ni + NaCl \rightarrow $[/tex] - No reaction (False)
4. [tex]$ Fe + Cu(NO_3)_2 \rightarrow $[/tex] - Reaction occurs (True)

Thus, the results we have for which reactants will form products are:

[tex]\[ [False, False, False, True] \][/tex]