\begin{tabular}{|c|c|c|}
\hline
Place & Is a city & Is in North America \\
\hline
Rome & v & \\
\hline
Tokyo & v & \\
\hline
Houston & v & v \\
\hline
Peru & & \\
\hline
Miami & v & v \\
\hline
Toronto & v & v \\
\hline
Canada & & v \\
\hline
\end{tabular}

Let event [tex]$A=$[/tex] The place is a city.
Let event [tex]$B=$[/tex] The place is in North America.

What is [tex]$P(A$[/tex] and [tex]$B)$[/tex]?

A. [tex]$\frac{3}{7}$[/tex]



Answer :

To solve for [tex]\( P(A \text{ and } B) \)[/tex], we need to find the probability that a place is both a city and in North America.

1. Count the total number of places listed in the table:

- Rome
- Tokyo
- Houston
- Peru
- Miami
- Toronto
- Canada

This gives us a total of [tex]\( 7 \)[/tex] places.

2. Identify the number of places that are both cities and in North America:

- Toronto is the only place that is both a city and in North America.

Therefore, the number of places that are both cities and in North America is [tex]\( 1 \)[/tex].

3. Calculate the probability [tex]\( P(A \text{ and } B) \)[/tex]:

[tex]\( P(A \text{ and } B) \)[/tex] is the number of places that are both cities and in North America divided by the total number of places.

[tex]\[ P(A \text{ and } B) = \frac{1}{7} \][/tex]

To summarize, the probability that a place is both a city and in North America is [tex]\( \frac{1}{7} \)[/tex] or approximately [tex]\( 0.14285714285714285 \)[/tex].