Which equation is perpendicular to:
[tex]\[ y = -6x + 2 \][/tex]

A. [tex]\( y = \frac{1}{6}x + 3 \)[/tex]
B. [tex]\( y = 6x - 1 \)[/tex]
C. [tex]\( y = -\frac{1}{6}x + 4 \)[/tex]
D. [tex]\( y = -6x + 5 \)[/tex]



Answer :

Answer:

A. [tex]y=\dfrac{1}{6}x+3[/tex]

Step-by-step explanation:

Perpendicularity

Determining if the slopes of two lines are negative reciprocals helps conclude if they're perpendicular.

Negative Reciprocals

Negative reciprocals are numbers where their numerator and denominator values are flipped and have opposite signs relative to the other.

For example,

[tex]\rm-2 \: and\: \dfrac{1}{2}[/tex] not only have different signs but the "invisible" 1 in the denominator of -2 is placed at the top as seen in [tex]\dfrac{1}{2}[/tex].

[tex]\hrulefill[/tex]

Solving the Problem

We need to find the negative reciprocal of -6.

Flipping the 6 and the "invisible" 1, and get rid of the negative sign we get, [tex]\dfrac{1}{6}[/tex].

Only answer choice A has a slope of one-sixth, so that's our answer.