Answer :

To find the value of the expression \(a^3 - 3a^2b + 3ab^2 - b^3\) for \(a = 2\) and \(b = 4\), follow these steps:

1. Substitute the values of \(a\) and \(b\) into the expression:
[tex]\[ 2^3 - 3 \cdot 2^2 \cdot 4 + 3 \cdot 2 \cdot 4^2 - 4^3 \][/tex]

2. Calculate each term separately:

- Compute \(2^3\):
[tex]\[ 2^3 = 8 \][/tex]

- Compute \(3 \cdot 2^2 \cdot 4\):
[tex]\[ 2^2 = 4 \quad \text{so} \quad 3 \cdot 4 \cdot 4 = 3 \cdot 16 = 48 \][/tex]

- Compute \(3 \cdot 2 \cdot 4^2\):
[tex]\[ 4^2 = 16 \quad \text{so} \quad 3 \cdot 2 \cdot 16 = 6 \cdot 16 = 96 \][/tex]

- Compute \(4^3\):
[tex]\[ 4^3 = 64 \][/tex]

3. Substitute these results back into the expression:

[tex]\[ 8 - 48 + 96 - 64 \][/tex]

4. Simplify the expression step-by-step:

- First add and subtract from left to right:
[tex]\[ 8 - 48 = -40 \][/tex]

Then add the next term:
[tex]\[ -40 + 96 = 56 \][/tex]

Finally, subtract the last term:
[tex]\[ 56 - 64 = -8 \][/tex]

So, the value of the expression \(a^3 - 3a^2b + 3ab^2 - b^3\) when \(a = 2\) and \(b = 4\) is:
[tex]\(\boxed{-8}\)[/tex]