Answer :
To find the product of [tex]\(8,029\)[/tex] and [tex]\(7\)[/tex]:
1. Set up the multiplication:
[tex]\[ 8,029 \times 7 \][/tex]
2. Multiply each digit of [tex]\(8,029\)[/tex] by [tex]\(7\)[/tex], starting from the rightmost digit:
- [tex]\(9 \times 7 = 63\)[/tex]. Write down [tex]\(3\)[/tex] and carry over [tex]\(6\)[/tex].
- [tex]\(2 \times 7 = 14\)[/tex]. Add the carry-over [tex]\(6\)[/tex] to get [tex]\(20\)[/tex]. Write down [tex]\(0\)[/tex] and carry over [tex]\(2\)[/tex].
- [tex]\(0 \times 7 = 0\)[/tex]. Add the carry-over [tex]\(2\)[/tex] to get [tex]\(2\)[/tex]. Write down [tex]\(2\)[/tex].
- [tex]\(8 \times 7 = 56\)[/tex]. Write down [tex]\(56\)[/tex].
3. Combine the results:
- The digits from right to left are [tex]\(3, 0, 2, 6, 5\)[/tex].
Thus, the complete product is:
[tex]\[ 8,029 \times 7 = 56,203 \][/tex]
The correct answer is:
[tex]\[ \boxed{56,203} \][/tex]
1. Set up the multiplication:
[tex]\[ 8,029 \times 7 \][/tex]
2. Multiply each digit of [tex]\(8,029\)[/tex] by [tex]\(7\)[/tex], starting from the rightmost digit:
- [tex]\(9 \times 7 = 63\)[/tex]. Write down [tex]\(3\)[/tex] and carry over [tex]\(6\)[/tex].
- [tex]\(2 \times 7 = 14\)[/tex]. Add the carry-over [tex]\(6\)[/tex] to get [tex]\(20\)[/tex]. Write down [tex]\(0\)[/tex] and carry over [tex]\(2\)[/tex].
- [tex]\(0 \times 7 = 0\)[/tex]. Add the carry-over [tex]\(2\)[/tex] to get [tex]\(2\)[/tex]. Write down [tex]\(2\)[/tex].
- [tex]\(8 \times 7 = 56\)[/tex]. Write down [tex]\(56\)[/tex].
3. Combine the results:
- The digits from right to left are [tex]\(3, 0, 2, 6, 5\)[/tex].
Thus, the complete product is:
[tex]\[ 8,029 \times 7 = 56,203 \][/tex]
The correct answer is:
[tex]\[ \boxed{56,203} \][/tex]
