Perform the indicated operation and simplify the result. Leave your answer in factored form.

[tex]\[
\frac{9+\frac{1}{x}}{8-\frac{1}{x}}
\][/tex]

[tex]\[
\frac{9+\frac{1}{x}}{8-\frac{1}{x}} = \quad \text{(Simplify your answer. Use integers or fractions for any numbers in the expression.)}
\][/tex]



Answer :

To simplify the given expression [tex]\(\frac{9+\frac{1}{x}}{8-\frac{1}{x}}\)[/tex], follow these steps:

1. Combine the terms to have a single fraction:
The given expression is [tex]\(\frac{9 + \frac{1}{x}}{8 - \frac{1}{x}}\)[/tex].

2. Rewrite each term with a common denominator:
To combine the terms inside the fractions on the numerator and the denominator, we'll express everything with the common denominator [tex]\(x\)[/tex]:
[tex]\[ 9 + \frac{1}{x} = \frac{9x}{x} + \frac{1}{x} = \frac{9x + 1}{x} \][/tex]
[tex]\[ 8 - \frac{1}{x} = \frac{8x}{x} - \frac{1}{x} = \frac{8x - 1}{x} \][/tex]

3. Rewrite the entire expression:
Substituting these into the original fraction, we get:
[tex]\[ \frac{\frac{9x + 1}{x}}{\frac{8x - 1}{x}} \][/tex]

4. Simplify the compound fraction:
Because both the numerator and the denominator have the same denominator [tex]\(x\)[/tex], they can be simplified:
[tex]\[ \frac{\frac{9x + 1}{x}}{\frac{8x - 1}{x}} = \frac{9x + 1}{8x - 1} \][/tex]

Thus, the simplified form of the fraction is:
[tex]\[ \frac{9x + 1}{8x - 1} \][/tex]

This is the simplified and factored form of the original expression.