If you place a [tex]\(+0.638 \, \text{C}\)[/tex] charge at a point where the electric field is [tex]\(27.4 \, \text{N/C}\)[/tex] to the right, what electric force will it feel?

Include a + or - sign to indicate the direction of the force.
(Unit = N)



Answer :

To determine the electric force [tex]\( F \)[/tex] felt by a charge [tex]\( q \)[/tex] placed in an electric field [tex]\( E \)[/tex], we can use the formula:

[tex]\[ F = qE \][/tex]

Given:
- The charge [tex]\( q \)[/tex] is [tex]\( +0.638 \, \text{C} \)[/tex]
- The electric field [tex]\( E \)[/tex] is [tex]\( 27.4 \, \text{N/C} \)[/tex] to the right

Substitute the values into the formula:

[tex]\[ F = (+0.638 \, \text{C}) \times (27.4 \, \text{N/C}) \][/tex]

Multiply these values together:

[tex]\[ F = 0.638 \times 27.4 \][/tex]

[tex]\[ F = 17.4812 \, \text{N} \][/tex]

The direction of the electric force is determined by the direction of the electric field and the sign of the charge:
- Since the electric field is to the right and the charge is positive, the force will also be to the right.

Therefore, the electric force felt by the charge is:

[tex]\[ F = +17.4812 \, \text{N} \][/tex]

The positive sign indicates that the direction of the force is to the right.

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