Answer:
Given data:
Volume of solution, V = 121.20 mL = 0.1212 L
Mass of protein, m = 1.26 g
Osmotic pressure, π = 2.57 x 10^-3 bar
Temperature, T = 300 K
Universal gas constant, R = 0.083 L bar mol^-1 K^-1
We can use the formula for osmotic pressure: π = (n/V)RT, where n is the number of moles of solute.
First, we need to calculate the number of moles of protein: n = m / M, where M is the molar mass of the protein.
Next, we can rearrange the formula for osmotic pressure to solve for the molar mass, M: M=m/n
Substitute the values into the equations: n = 1.26 g / M π = (n / V)RT
Now, rearrange the osmotic pressure formula to solve for M: M = m / (πV/RT)
Substitute the given values into the equation and solve for M: M=1.26 g/((2.57 x 10^-3 bar)* 0.1212 L/ (0.083 L bar mol^-1 K^-1* 300 K))
Calculating the value of M will give the molar mass of the protein in grams per mole.
Therefore, the molar mass of the protein will be calculated to
determine which option it matches with:
(a) 51022 g/mol
(b) 122044 g/mol
(c) 31011 g/mol
(d) 61038 g/mol
Please calculate the final answer accordingly.
