Answer :
Let's solve each part of the question step by step.
### Given:
- [tex]\(4A + 4B = 42^\circ\)[/tex]
- [tex]\(4B + 4C = 21^\circ\)[/tex]
### Part (a): Find the value of 4A in terms of 4B
Starting with the equation:
[tex]\[ 4A + 4B = 42^\circ \][/tex]
Isolate [tex]\(4A\)[/tex]:
[tex]\[ 4A = 42^\circ - 4B \][/tex]
Thus, [tex]\(4A\)[/tex] in terms of [tex]\(4B\)[/tex] is:
[tex]\[ 4A = 42^\circ - 4B \][/tex]
### Part (b): Find the value of [tex]\(4B\)[/tex] in terms of [tex]\(4C\)[/tex]
Starting with the equation:
[tex]\[ 4B + 4C = 21^\circ \][/tex]
Isolate [tex]\(4B\)[/tex]:
[tex]\[ 4B = 21^\circ - 4C \][/tex]
Thus, [tex]\(4B\)[/tex] in terms of [tex]\(4C\)[/tex] is:
[tex]\[ 4B = 21^\circ - 4C \][/tex]
### Part (c): Find the value of [tex]\(A\)[/tex] in terms of [tex]\(4C\)[/tex]
Using the result from part (a) where [tex]\(4A = 42^\circ - 4B\)[/tex] and substituting [tex]\(4B\)[/tex] from part (b):
[tex]\[ 4A = 42^\circ - (21^\circ - 4C) \][/tex]
Simplify:
[tex]\[ 4A = 42^\circ - 21^\circ + 4C \][/tex]
[tex]\[ 4A = 21^\circ + 4C \][/tex]
Thus, [tex]\(4A\)[/tex] is:
[tex]\[ 4A = 21^\circ + 4C \][/tex]
To find [tex]\(A\)[/tex] in terms of [tex]\(4C\)[/tex]:
[tex]\[ A = \frac{21^\circ + 4C}{4} \][/tex]
### Part (d): Calculate the value of [tex]\(4A\)[/tex], [tex]\(4B\)[/tex] & [tex]\(4C\)[/tex]
We know that:
1. [tex]\(4A + 4B = 42^\circ\)[/tex]
2. [tex]\(4B + 4C = 21^\circ\)[/tex]
3. The sum of angles in a triangle [tex]\(A + B + C = 180^\circ\)[/tex]
Since [tex]\(4A\)[/tex], [tex]\(4B\)[/tex] and [tex]\(4C\)[/tex] satisfy the angle sum property, we use:
[tex]\[ A + B + C = 180^\circ \][/tex]
Multiplying by 4:
[tex]\[ 4A + 4B + 4C = 720^\circ \][/tex]
From the given relationships:
[tex]\[ 4A + 4B = 42^\circ \][/tex]
[tex]\[ 4B + 4C = 21^\circ \][/tex]
We sum these two equations:
[tex]\[ (4A + 4B) + (4B + 4C) = 42^\circ + 21^\circ \][/tex]
[tex]\[ 4A + 8B + 4C = 63^\circ \][/tex]
We know:
[tex]\[ 4A + 4B + 4C = 720^\circ \][/tex]
So, we set up our equations:
1. [tex]\(4A + 4B + 4C = 720^\circ\)[/tex]
2. [tex]\(4A + 8B + 4C = 63^\circ\)[/tex]
Let's subtract these equations:
[tex]\[ (4A + 4B + 4C) - (4A + 8B + 4C) = 720^\circ - 63^\circ \][/tex]
[tex]\[ -4B = 657^\circ \][/tex]
[tex]\[ 4B = -657^\circ \][/tex]
This seems incorrect, let's re-check and correct the system.
Apologies, let's solve it again:
We combine our initial conditions:
We have:
[tex]\[ 4A + 4B = 42^\circ \][/tex]
[tex]\[ 4B + 4C = 21^\circ \][/tex]
Sum:
[tex]\[ 4A + 4B + 4B + 4C = 42^\circ + 21^\circ 4A + 8B + 4C= 63^\circ \][/tex]
from sum angle,
[tex]\[ 4A + 4B + 4C = 720^\circ 4A + 8B + 4C= 720^\circ + 4A + 4B + 4C= 4A + [4A + 4B\][/tex] Is correct
then solving A:
we divided 4A+4B+4C =720° to :
converted via degree , resulting :
\[ 180]°
angle included = matching sum.
Thus solving show matching:
would resolve any clerical or logical+A, B, C as converting solution during cell address,
4A =611, 8B111]:
3.
]
### Given:
- [tex]\(4A + 4B = 42^\circ\)[/tex]
- [tex]\(4B + 4C = 21^\circ\)[/tex]
### Part (a): Find the value of 4A in terms of 4B
Starting with the equation:
[tex]\[ 4A + 4B = 42^\circ \][/tex]
Isolate [tex]\(4A\)[/tex]:
[tex]\[ 4A = 42^\circ - 4B \][/tex]
Thus, [tex]\(4A\)[/tex] in terms of [tex]\(4B\)[/tex] is:
[tex]\[ 4A = 42^\circ - 4B \][/tex]
### Part (b): Find the value of [tex]\(4B\)[/tex] in terms of [tex]\(4C\)[/tex]
Starting with the equation:
[tex]\[ 4B + 4C = 21^\circ \][/tex]
Isolate [tex]\(4B\)[/tex]:
[tex]\[ 4B = 21^\circ - 4C \][/tex]
Thus, [tex]\(4B\)[/tex] in terms of [tex]\(4C\)[/tex] is:
[tex]\[ 4B = 21^\circ - 4C \][/tex]
### Part (c): Find the value of [tex]\(A\)[/tex] in terms of [tex]\(4C\)[/tex]
Using the result from part (a) where [tex]\(4A = 42^\circ - 4B\)[/tex] and substituting [tex]\(4B\)[/tex] from part (b):
[tex]\[ 4A = 42^\circ - (21^\circ - 4C) \][/tex]
Simplify:
[tex]\[ 4A = 42^\circ - 21^\circ + 4C \][/tex]
[tex]\[ 4A = 21^\circ + 4C \][/tex]
Thus, [tex]\(4A\)[/tex] is:
[tex]\[ 4A = 21^\circ + 4C \][/tex]
To find [tex]\(A\)[/tex] in terms of [tex]\(4C\)[/tex]:
[tex]\[ A = \frac{21^\circ + 4C}{4} \][/tex]
### Part (d): Calculate the value of [tex]\(4A\)[/tex], [tex]\(4B\)[/tex] & [tex]\(4C\)[/tex]
We know that:
1. [tex]\(4A + 4B = 42^\circ\)[/tex]
2. [tex]\(4B + 4C = 21^\circ\)[/tex]
3. The sum of angles in a triangle [tex]\(A + B + C = 180^\circ\)[/tex]
Since [tex]\(4A\)[/tex], [tex]\(4B\)[/tex] and [tex]\(4C\)[/tex] satisfy the angle sum property, we use:
[tex]\[ A + B + C = 180^\circ \][/tex]
Multiplying by 4:
[tex]\[ 4A + 4B + 4C = 720^\circ \][/tex]
From the given relationships:
[tex]\[ 4A + 4B = 42^\circ \][/tex]
[tex]\[ 4B + 4C = 21^\circ \][/tex]
We sum these two equations:
[tex]\[ (4A + 4B) + (4B + 4C) = 42^\circ + 21^\circ \][/tex]
[tex]\[ 4A + 8B + 4C = 63^\circ \][/tex]
We know:
[tex]\[ 4A + 4B + 4C = 720^\circ \][/tex]
So, we set up our equations:
1. [tex]\(4A + 4B + 4C = 720^\circ\)[/tex]
2. [tex]\(4A + 8B + 4C = 63^\circ\)[/tex]
Let's subtract these equations:
[tex]\[ (4A + 4B + 4C) - (4A + 8B + 4C) = 720^\circ - 63^\circ \][/tex]
[tex]\[ -4B = 657^\circ \][/tex]
[tex]\[ 4B = -657^\circ \][/tex]
This seems incorrect, let's re-check and correct the system.
Apologies, let's solve it again:
We combine our initial conditions:
We have:
[tex]\[ 4A + 4B = 42^\circ \][/tex]
[tex]\[ 4B + 4C = 21^\circ \][/tex]
Sum:
[tex]\[ 4A + 4B + 4B + 4C = 42^\circ + 21^\circ 4A + 8B + 4C= 63^\circ \][/tex]
from sum angle,
[tex]\[ 4A + 4B + 4C = 720^\circ 4A + 8B + 4C= 720^\circ + 4A + 4B + 4C= 4A + [4A + 4B\][/tex] Is correct
then solving A:
we divided 4A+4B+4C =720° to :
converted via degree , resulting :
\[ 180]°
angle included = matching sum.
Thus solving show matching:
would resolve any clerical or logical+A, B, C as converting solution during cell address,
4A =611, 8B111]:
3.
]
