To determine how much work is being done by the construction worker carrying a load, let's analyze the situation step-by-step:
1. Understanding Work Done:
- Work is defined as the product of the force applied and the distance over which the force is applied, aligned in the direction of the force.
- The formula for work done ([tex]\(W\)[/tex]) is given by: [tex]\( W = F \cdot d \cdot \cos(\theta) \)[/tex]
- [tex]\(F\)[/tex] is the force.
- [tex]\(d\)[/tex] is the distance moved.
- [tex]\(\theta\)[/tex] is the angle between the force and the direction of movement.
- [tex]\(\cos(\theta)\)[/tex] is the cosine of that angle.
2. Analyzing the Situation:
- The construction worker is carrying a 40 kg load over his head.
- The force due to gravity is acting vertically downwards.
- The worker is traveling horizontally.
- Thus, the angle [tex]\(\theta\)[/tex] between the force (downwards) and the direction of movement (horizontal) is 90 degrees.
3. Cosine of the Angle:
- [tex]\(\cos(90^\circ)\)[/tex] = 0.
4. Substituting Values:
- Even though we know the force and distance, the key here is [tex]\(\cos(90^\circ)\)[/tex] = 0.
- Therefore, [tex]\( W = F \cdot d \cdot \cos(90^\circ) = F \cdot d \cdot 0 = 0 \)[/tex].
### Conclusion:
The work done by the construction worker in this scenario is [tex]\(0\)[/tex] joules.
Thus, the correct answer is:
A. 0 joules
