Applicants to a university were surveyed about their planned living arrangements for the coming year. The results of the survey are displayed in the two-way frequency table.

\begin{tabular}{|l|c|c|c|}
\cline { 2 - 4 }
\multicolumn{1}{c|}{} & On-Campus & Off-Campus & Total \\
\hline
Transfer Applicants & 38 & 66 & 104 \\
\hline
Freshman Applicants & 85 & 52 & 137 \\
\hline
Total & 123 & 118 & 241 \\
\hline
\end{tabular}

What is the probability that an applicant planning to stay off-campus is a transfer applicant?

A. 0.490
B. 0.559
C. 0.635
D. 0.525



Answer :

Certainly! Let's solve the given problem step-by-step to find the probability that an applicant planning to stay off-campus is a transfer applicant.

1. Identify the given data:
- Number of transfer applicants who plan to live off-campus: [tex]\( 66 \)[/tex]
- Total number of applicants who plan to live off-campus: [tex]\( 118 \)[/tex]

2. Define the probability formula:
The probability [tex]\( P \)[/tex] that an applicant planning to stay off-campus is a transfer applicant is given by:
[tex]\[ P(\text{Transfer} | \text{Off-Campus}) = \frac{\text{Number of transfer applicants planning to live off-campus}}{\text{Total number of applicants planning to live off-campus}} \][/tex]

3. Substitute the given values into the formula:
[tex]\[ P(\text{Transfer} | \text{Off-Campus}) = \frac{66}{118} \][/tex]

4. Calculate the probability:
[tex]\[ P(\text{Transfer} | \text{Off-Campus}) \approx 0.559 \][/tex]

5. Match the calculated probability with the given choices:
The calculated probability [tex]\( 0.559 \)[/tex] matches choice B.

Therefore, the probability that an applicant planning to stay off-campus is a transfer applicant is:
[tex]\[ \boxed{0.559} \][/tex]