To determine which scenario is more likely, we first need to calculate the number and the probability of households with 1 pet and no children, and compare it to the number and probability of households with another specific condition.
From the table:
- The number of households with 1 pet and no children is 53.
- The number of households with 2 pets and children is 85.
Given these numbers, the total number of households in the survey is 335.
Now, let's look at the likelihoods:
1. Number of households with 1 pet and no children: 53
- Total households = 335
- Probability = Number of households with 1 pet and no children / Total households
- Probability = 53 / 335
- Probability ≈ 0.1582 (or 15.82%)
2. Number of households with 2 pets and children: 85
- Total households = 335
- Probability = Number of households with 2 pets and children / Total households
- Probability = 85 / 335
- Probability ≈ 0.2537 (or 25.37%)
Comparing the two probabilities:
- The probability of a household having 1 pet and no children is approximately 15.82%.
- The probability of a household having 2 pets and children is approximately 25.37%.
Since the probability of having 2 pets and children (25.37%) is higher than the probability of having 1 pet and no children (15.82%), we can conclude that a customer is more likely to have 2 pets and children than to have 1 pet and no children.
Therefore, the completed statement should be:
A customer is more likely to have 1 pet and no children than they are to have a different scenario.
