To determine which element has the given electron configuration, let's analyze the configuration step by step.
Firstly, note that the electron configuration specifies the way electrons are distributed in an atom's orbitals.
Here, the configuration provided is:
- 1s: [tex]$\uparrow \downarrow$[/tex]
- 2s: [tex]$\uparrow \downarrow$[/tex]
- 2p: [tex]$\uparrow \downarrow$[/tex] [tex]$\uparrow \downarrow$[/tex] [tex]$\uparrow \downarrow$[/tex]
- 3s: [tex]$\uparrow \downarrow$[/tex]
- 3p: [tex]$\uparrow$[/tex] [tex]$\uparrow$[/tex] [tex]$\uparrow$[/tex]
Let's break down the given electron configuration:
1. 1s Orbital:
- [tex]$\uparrow \downarrow$[/tex] indicates 2 electrons in the 1s orbital.
2. 2s Orbital:
- [tex]$\uparrow \downarrow$[/tex] indicates 2 electrons in the 2s orbital.
3. 2p Orbitals:
- Three 2p orbitals, each holds up to 2 electrons:
- [tex]$\uparrow \downarrow$[/tex]
- [tex]$\uparrow \downarrow$[/tex]
- [tex]$\uparrow \downarrow$[/tex]
- Total electrons in 2p orbitals: 6 electrons.
4. 3s Orbital:
- [tex]$\uparrow \downarrow$[/tex] indicates 2 electrons in the 3s orbital.
5. 3p Orbitals:
- Three 3p orbitals, with:
- [tex]$\uparrow$[/tex]
- [tex]$\uparrow$[/tex]
- [tex]$\uparrow$[/tex]
- Total electrons in the 3p orbitals: 3 electrons.
Adding electrons from each orbital, we get:
- 1s: 2 electrons
- 2s: 2 electrons
- 2p: 6 electrons
- 3s: 2 electrons
- 3p: 3 electrons
Summing these up gives:
[tex]\[2 + 2 + 6 + 2 + 3 = 15\][/tex]
This configuration corresponds to an element with 17 electrons, which is the number of electrons in a neutral chlorine atom (atomic number 17).
Therefore, the element that has this electron configuration is Chlorine.
So, the correct answer is:
chlorine
