A company designs a logo using a kite figure around the letter [tex]$t$[/tex].

The logo is 12 centimeters wide and 16 centimeters tall. What is the area of the logo?

A. 48 sq. cm
B. 96 sq. cm
C. 144 sq. cm
D. 192 sq. cm



Answer :

To determine the area of a kite, you can use the formula for the area of a kite, which is given by:

[tex]\[ \text{Area} = \frac{1}{2} \times \text{diagonal}_1 \times \text{diagonal}_2 \][/tex]

In this context, the width and height of the kite act as the lengths of the diagonals of the kite. The dimensions provided for the kite are:
- Width = 12 cm
- Height = 16 cm

Plugging these values into the formula:

[tex]\[ \text{Area} = \frac{1}{2} \times 12 \, \text{cm} \times 16 \, \text{cm} \][/tex]

First, calculate the product of the diagonals:

[tex]\[ 12 \, \text{cm} \times 16 \, \text{cm} = 192 \, \text{cm}^2 \][/tex]

Then, multiply by [tex]\(\frac{1}{2}\)[/tex]:

[tex]\[ \frac{1}{2} \times 192 \, \text{cm}^2 = 96 \, \text{cm}^2 \][/tex]

Therefore, the area of the logo is:

[tex]\[ \boxed{96 \, \text{sq. cm}} \][/tex]

Other Questions