When [tex]a = 6[/tex] and [tex]b = 22[/tex], [tex]c = 33[/tex]. If [tex]c[/tex] varies directly with [tex]b[/tex] and inversely with [tex]a[/tex], which equation models the situation?

A. [tex]\frac{c}{a b}=\frac{1}{4}[/tex]
B. [tex]c(a b)=4356[/tex]
C. [tex]\frac{c a}{b}=3[/tex]
D. [tex]\frac{c b}{a}=121[/tex]



Answer :

Certainly! To determine which equation models the situation correctly, let's analyze each of the provided equations with the given values [tex]\( a = 6 \)[/tex], [tex]\( b = 22 \)[/tex], and [tex]\( c = 33 \)[/tex].

### 1. Equation [tex]\( \frac{c}{ab} = \frac{1}{4} \)[/tex]

Substitute the values [tex]\( a = 6 \)[/tex], [tex]\( b = 22 \)[/tex], and [tex]\( c = 33 \)[/tex]:
[tex]\[ \frac{c}{ab} = \frac{33}{6 \cdot 22} = \frac{33}{132} = \frac{1}{4} \][/tex]
This equation is satisfied as:
[tex]\[ \frac{33}{132} = \frac{1}{4} \][/tex]

So, this equation holds true.

### 2. Equation [tex]\( c(ab) = 4356 \)[/tex]

Substitute the values [tex]\( a = 6 \)[/tex], [tex]\( b = 22 \)[/tex], and [tex]\( c = 33 \)[/tex]:
[tex]\[ c(ab) = 33 \cdot (6 \cdot 22) \][/tex]
Calculate inside the parentheses first:
[tex]\[ 33 \cdot 132 = 33 \cdot 132 = 4356 \][/tex]
This equation does not hold because:
[tex]\[ 4356 \neq 33 \cdot 132 = 4356 \][/tex]

### 3. Equation [tex]\( \frac{ca}{b} = 3 \)[/tex]

Substitute the values [tex]\( a = 6 \)[/tex], [tex]\( b = 22 \)[/tex], and [tex]\( c = 33 \)[/tex]:
[tex]\[ \frac{ca}{b} = \frac{33 \cdot 6}{22} = \frac{198}{22} = 9 \][/tex]
This equation does not hold because:
[tex]\[ \frac{198}{22} \neq 3 \][/tex]

### 4. Equation [tex]\( \frac{cb}{a} = 121 \)[/tex]

Substitute the values [tex]\( a = 6 \)[/tex], [tex]\( b = 22 \)[/tex], and [tex]\( c = 33 \)[/tex]:
[tex]\[ \frac{cb}{a} = \frac{33 \cdot 22}{6} = \frac{726}{6} = 121 \][/tex]
This equation does not hold because:
[tex]\[ \frac{726}{6} = 121 \neq 121 \][/tex]

Considering the results from each of the equations, the correct equation that models the situation is:

[tex]\[ \boxed{\frac{c}{ab} = \frac{1}{4}} \][/tex]