Complete the remainder of the table for the given function rule:
[tex]\[ y = -x - 9 \][/tex]

[tex]\[
\begin{tabular}{c|ccccc}
x & -2 & -1 & 0 & 1 & 2 \\
\hline
y & -7 & {?} & {?} & {?} & {?} \\
\end{tabular}
\][/tex]



Answer :

Certainly! Let's complete the table for the given function rule [tex]\( y = -x - 9 \)[/tex]. We'll determine the values of [tex]\( y \)[/tex] corresponding to each given [tex]\( x \)[/tex] value.

Given [tex]\( x \)[/tex] values are: [tex]\( -2, -1, 0, 1, 2 \)[/tex].

1. For [tex]\( x = -2 \)[/tex]:
[tex]\[ y = -(-2) - 9 = 2 - 9 = -7 \][/tex]
So, [tex]\( y = -7 \)[/tex].

2. For [tex]\( x = -1 \)[/tex]:
[tex]\[ y = -(-1) - 9 = 1 - 9 = -8 \][/tex]
So, [tex]\( y = -8 \)[/tex].

3. For [tex]\( x = 0 \)[/tex]:
[tex]\[ y = -(0) - 9 = 0 - 9 = -9 \][/tex]
So, [tex]\( y = -9 \)[/tex].

4. For [tex]\( x = 1 \)[/tex]:
[tex]\[ y = -(1) - 9 = -1 - 9 = -10 \][/tex]
So, [tex]\( y = -10 \)[/tex].

5. For [tex]\( x = 2 \)[/tex]:
[tex]\[ y = -(2) - 9 = -2 - 9 = -11 \][/tex]
So, [tex]\( y = -11 \)[/tex].

Now, we can complete the table:

[tex]\[ \begin{array}{l|lllll} \text{x} & -2 & -1 & 0 & 1 & 2 \\ \hline \text{y} & -7 & -8 & -9 & -10 & -11 \\ \end{array} \][/tex]