A particle moves in the [tex]XY[/tex] plane with constant acceleration [tex]a[/tex] directed along the negative [tex]y[/tex]-axis. The equation of motion of the particle has the form [tex]y = px - qx^2[/tex], where [tex]p[/tex] and [tex]q[/tex] are positive constants. If the velocity of the particle at the origin is [tex]u = \sqrt{\frac{a\left(x + p^2\right)}{yq}}[/tex], then [tex]x + y = \ \ \ \ \ \ \ \ \ \ \].



Answer :

To solve the problem, let's go step-by-step through the provided information and the required calculations.

1. Particle's Equation of Motion:
Given the equation of motion of the particle:
[tex]\[ y = px - qx^2 \][/tex]
Here, [tex]\( p \)[/tex] and [tex]\( q \)[/tex] are positive constants.

2. Velocity at the Origin:
Given the velocity of the particle at the origin:
[tex]\[ u = \sqrt{\frac{a(x + p^2)}{y q}} \][/tex]
This expression gives us the velocity at the origin where [tex]\(x = 0\)[/tex] and [tex]\(y = 0\)[/tex].

3. Formulate the Expression for [tex]\( x + y \)[/tex]:
To find [tex]\( x + y \)[/tex], we need an expression for [tex]\( y \)[/tex] in terms of [tex]\( x \)[/tex] from the given equation of motion.

The given equation of motion simplifies to:
[tex]\[ y = px - qx^2 \][/tex]

Substituting this into [tex]\( x + y \)[/tex] gives us:
[tex]\[ x + y = x + (px - qx^2) \][/tex]

4. Combine the Terms:
Combine like terms in the expression:
[tex]\[ x + (px - qx^2) = x + px - qx^2 \][/tex]

5. Simplify the Expression:
Factor out the common term [tex]\( x \)[/tex]:
[tex]\[ x(1 + p - qx) \][/tex]

6. Final Simplified Expression:
Hence, the expression for [tex]\( x + y \)[/tex]:
[tex]\[ x + y = x(p - qx) + x \][/tex]
So the final answer is:
[tex]\[ x(p - qx) + x \][/tex]

Thus, the value of [tex]\( x + y \)[/tex] can be expressed as [tex]\( x(p - qx) + x \)[/tex].