Select the correct answer.

The concession stand at the high school football stadium sells hot dogs and hamburgers to raise money for the high school athletic programs. Each hot dog sold earns the programs [tex]$\$[/tex]0.50[tex]$, and each hamburger sold earns $[/tex]\[tex]$0.75$[/tex]. This week, the concession stand sold a combination of 230 hot dogs and hamburgers and earned [tex]$\$[/tex]138.50[tex]$ for the athletic programs. If $[/tex]x[tex]$ represents the number of hot dogs sold and $[/tex]y[tex]$ represents the number of hamburgers sold, which system of equations represents this situation?

A. $[/tex]0.50x + 0.75y = 138.50[tex]$
$[/tex]x + y = 230[tex]$

B. $[/tex]0.75x + 0.50y = 230[tex]$
$[/tex]x + y = 138.50[tex]$

C. $[/tex]0.75x + 0.50y = 138.50[tex]$
$[/tex]x + y = 230[tex]$

D. $[/tex]0.50x + 0.75y = 230[tex]$
$[/tex]x + y = 138.50$



Answer :

To determine the correct system of equations representing the given situation, we need to analyze the conditions provided:

1. Each hot dog sold earns \[tex]$0.50. 2. Each hamburger sold earns \$[/tex]0.75.
3. The total number of hot dogs and hamburgers sold is 230.
4. The total revenue earned from the sales of hot dogs and hamburgers is \$138.50.
5. Let [tex]\(x\)[/tex] represent the number of hot dogs sold and [tex]\(y\)[/tex] represent the number of hamburgers sold.

To set up the equations, we translate the given conditions into mathematical expressions:

First Equation (Revenue Equation):
The revenue generated from selling [tex]\(x\)[/tex] hot dogs and [tex]\(y\)[/tex] hamburgers can be expressed as:
[tex]\[0.50x + 0.75y = 138.50\][/tex]

Second Equation (Total Quantity Equation):
The total number of hot dogs and hamburgers sold is given by:
[tex]\[x + y = 230\][/tex]

Therefore, the system of equations representing this situation is:
[tex]\[ \begin{cases} 0.50x + 0.75y = 138.50 \\ x + y = 230 \end{cases} \][/tex]

Upon comparing with the options provided, we see that:

- Option A: [tex]\(0.50x + 0.75y = 138.50 \quad\text{and}\quad x + y = 230\)[/tex]

This matches our derived system of equations perfectly.

Hence, the correct answer is:
[tex]\[ \boxed{\text{A}} \][/tex]